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In ∆ABC, AB = 10, AC = 7, BC = 9, then find the length of the median drawn from point C to side AB.

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Let CD be the median drawn from the vertex C to side AB.

\(BD = \frac{1}{2} AB\) [D is the midpoint of AB]

\(=\frac{1}{2} \times 10\) = 5 units

In ∆ABC, seg CD is the median. [Given]

∴ The length of the median drawn from point C to side AB is 2√10 units.

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