Use app×
Join Bloom Tuition
One on One Online Tuition
JEE MAIN 2025 Foundation Course
NEET 2025 Foundation Course
CLASS 12 FOUNDATION COURSE
CLASS 10 FOUNDATION COURSE
CLASS 9 FOUNDATION COURSE
CLASS 8 FOUNDATION COURSE
0 votes
155 views
in Quadratic Equations by (34.1k points)
closed by

Find m, if (m – 12) x2 + 2(m – 12) x + 2 = 0 has real and equal roots.

1 Answer

+1 vote
by (33.5k points)
selected by
 
Best answer

(m – 12) x2 + 2(m – 12)x + 2 = 0

Comparing the above equation with

ax2 + bx + c = 0, we get

a = m – 12, b = 2(m – 12), c = 2

Since, the roots are real and equal.

∴ ∆ = 0

∴ 4(m – 12) (m – 14) = 0 (m – 12) (m – 14) = 0

By using the property, if the product of two numbers is zero, then at least one of them is zero, we get

∴ m – 12 = 0 or m – 14 = 0 

∴ m = 12 or m = 14

But ,if m = 12, then quadratic coefficient becomes zero.

∴ m ≠ 12 

∴ m = 14

Welcome to Sarthaks eConnect: A unique platform where students can interact with teachers/experts/students to get solutions to their queries. Students (upto class 10+2) preparing for All Government Exams, CBSE Board Exam, ICSE Board Exam, State Board Exam, JEE (Mains+Advance) and NEET can ask questions from any subject and get quick answers by subject teachers/ experts/mentors/students.

...