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The equilibrium constant for a gaseous reversible reaction at 200°C is 1.64 × 103 atm2.Calculate ΔG0 for the reaction.

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Given : 

Equilibrium constant = KP = 1.64 × 103 atm2

Temperature = T = 273 + 200 = 473 K

ΔG0 = ?

ΔG0 = -2.303 RTlog10Kp

= – 2.303 × 8.314 × 473 × log101.64 × 103

= – 2.303 × 8.314 × 473 × (3.2148)

= -29115 J

= -29.115 kJ

∴ ΔG0 = -29.115 kJ

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