Question

If NaOH is added to an aqueous solution of `Zn^(+2)` ions white precipitate appears and on adding excess NaOH, the precipitate dissolves. In solution zinc is in the
A. Cationic part
B. Anionic part
C. Both in cationic and anionic parts
D. There is no zinc left in the solution.

Answer 1

Correct Answer - B
`Zn^(2+)+2NaOHrarr2Na^(2+)+Zn(OH)_(2)`
`Zn(OH)_(2)+2NaOHrarrNa_(2)ZnO_(2)+2H_(2)O`
`Na_(2)ZnO_(2)` ionises as 2 `Na^(+)` and `[ZnO_(2)]^(2-)`
`therefore` Zinc occurs as anion.