Use app×
Join Bloom Tuition
One on One Online Tuition
JEE MAIN 2025 Foundation Course
NEET 2025 Foundation Course
CLASS 12 FOUNDATION COURSE
CLASS 10 FOUNDATION COURSE
CLASS 9 FOUNDATION COURSE
CLASS 8 FOUNDATION COURSE
0 votes
64 views
in Chemistry by (61.5k points)
closed by
An ester (A) with molecular formula `C_(9)H_(10) O_(2)` was treated with excess of `CH_(3)MgBr` and the compound so formed was treated with conc. `H_(2)SO_(4)` to form olefin (B). Ozonolysis of B gave ketone with formula `C_(8)H_(8)O` which shows positive iodoform test. The structure of A is
A. `C_(6)H_(5)COOC_(2)H_(5)`
B. `CH_(3)OCH_(2)COC_(6)H_(5)`
C. `CH_(3)CO - C_(6)H_(5) - COCH_(3)`
D. `C_(6)H_(5)COOC_(6)H_(5)`

1 Answer

0 votes
by (62.1k points)
selected by
 
Best answer
Correct Answer - A
`{:(" "O" "OH),(" ||"" |"),(underset((A))(C_(6)H_(5) C - OC_(2)H_(5)) underset(HOH)overset(2CH_(3)MgBr)rarr C_(6)H_(5) - C - CH_(3)),(" |"),(" "CH_(3)),(" "443K darr H_(2)SO_(4)),(C_(6)H_(5) - C = O + HCHO underset((ii) Zn //H_(2)O)overset((i)O_(3))larr C_(6)H_(5) - C = CH_(2)),(" |"" |"),(" "CH_(3)" " underset((B)"Alkane")(CH_(3))):}`

Welcome to Sarthaks eConnect: A unique platform where students can interact with teachers/experts/students to get solutions to their queries. Students (upto class 10+2) preparing for All Government Exams, CBSE Board Exam, ICSE Board Exam, State Board Exam, JEE (Mains+Advance) and NEET can ask questions from any subject and get quick answers by subject teachers/ experts/mentors/students.

Categories

...