Question

In the estimation of sulphur by carius method, 0.468 gm of an organic sulphur compound afforded 0.668 gm of barium sulphate. Find out the percentage of sulphur in the given compound.

Answer 1

Total mass of organic compound = 0.468 g [Given]
Mass of barium sulphate formed = 0.668 g [Given]
1 mol of `BaSO_(4)` = 233 g of `BaSO_(4)` = 32 g of sulphur
Thus, 0.668 g of `BaSO_(4)` contains `(32xx0.668)/233g` of sulphur = 0.0917 g of sulphur
Therefore, percentage of sulphur = `0.0197/0.468xx100=19.59%`
Hence, the percentage of sulphur in the given compound is 19.59 %.