Question

If the position of the electron is measured within an accuracy of `+- 0.002 nm`. Calculate the uncertainty in the momentum of the electron. Suppose the momentum of the electron is `h//4pi_(m)xx0.05 nm`, is there any problem in defining this value.

Answer 1

According to de Broglie’s expression,
`lambda = (h)/(mv)`
Substituting the values in the expression,
`lambda = (6.626 xx 10^(-34) Js)/((0.1 kg)(4.37 xx 10^(5) ms^(-1)))`
`lambda = 1.516 xx 10^(-38) m`