Correct Answer - `4.2154xx10^(23)` electrons
Molar mass of dinirogen `(N_(2))=28g mol^(-1)`
Thus, 1.4 g of `N_(2)=(1.4)/(28)=0.05 mol`
`=0.05xx6.02xx10^(23)` number of molecules
`=3.01xx10^(23)` number of molecules
Now, 1 molecule of `N_(2)` contains 14 electrons.
Therefore, `3.01xx10^(23)` molecules of `N_(2)` contains `=14xx3.01xx1023=4.214xx10^(23)` electrons
