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`34.05 mL` of phosphorus vapours weighs `0.0625 g` at `546^(@)C` and `0.1` bar pressure. What is the molar mass of phossphorus ?
A. `124 . 77 g mol^(-1)`
B. `1247 . 74 g mol ^(-1)`
C. `12 . 47 g mol^(-1)`
D. `30 g mol^(-1)`

1 Answer

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Best answer
Correct Answer - B
`M=(mRT)/(PV)=(0.0625xx0.083xx819)/(0.1xx(34.05//1000))`
`=1247.74 g mol^(-1)`

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