Correct Answer - A
`underset("a moles")(HCOOH) overset(H_(2)SO_(4))underset(("Conc"))rarr H_(2)O +underset("a moles")(CO)`
`underset("a moles")(H_(2)C_(2)O_(4)) overset(H_(2)SO_(4))underset(("Conc"))rarr H_(2)O +underset("b moles")(CO)+underset("b moles")(CO_(2))`
Total no. of moles released as gases `a +b +b = a +2b`
`CO_(2)` is absorbed by KOH
`b = (1)/(6) (a+2b)` (moles `oo` volume)
`(a)/(b) = 4` or `a:b :: 4:1`