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`2NOCl(g) ltimplies 2NO(g) + Cl_(2)(g), K_( c)=3.75 xx 10^(-6)` उपरोक्त अभिक्रिया के लिए 1069 K पर `K_(p)` का मान ज्ञात करो।

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`K_(p) = K_( c)(RT)^(Deltan)`
`K_( c) = 3.75 xx 10^(-6), R=0.0821` लीटर वायुमंडल `K^(-1) मोल ^(-1)`
`T=1069 K, Deltan=1`
`K_(p) = 3.75 xx 10^(-6) xx 0.0821 xx 1069`
`=329.1 xx 10^(-6) = 3.29 xx 10^(-4)`

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