Correct Answer - 3
`30" vol"=3.05xx3=9.105%H_(2)O_(2)`
`100ml` sol contain `9.105` gms `H_(2)O_(2)`
Hence 1000ml solution contain `91.05` gms `H_(2)O_(2)`
Strength of `H_(2)O_(2)=91.05 ` gms`//` lit, basicity of `H_(2)O_(2)=2`
Equivalent wt. of `H_(2)O_(2)=((34)/(2))=17`
Normality `=("Strenth")/("Eq. wt")=(91.05)/(17)=5.3558`
`=5.36 " "Ans.`
