# How many millilitres of 0.5 M H_(2)SO_(4) are needed to dissolve 0.5 g of copper (II) Carbonate ?

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How many millilitres of 0.5 M H_(2)SO_(4) are needed to dissolve 0.5 g of copper (II) Carbonate ?

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Step I. Calculation of mass of H_(2)SO_(4)
The chemical equation for the reaction is :
underset(underset(=123.5g)(63.5+12+48))(CuCO_(3))+underset(underset(=98g)(2+32+64))(H_(2)SO_(4))rarrCuSO_(4)+CO_(2)+H_(2)O
123.5 of CuCO_(3) require H_(2)SO_(4)=98g
0.5 g of CuCO_(3) require H_(2)SO_(4)=(98)/(123.5)xx0.5=0.397g
Step II. Calculation of millilitres of H_(2)SO_(4)
Molarity of solution = ("Mass of "H_(2)SO_(4)//"Molar mass of "H_(2)SO_(4))/("Volume of solution in litres")
:. Volume of solution = ("Mass of "H_(2)SO_(4)//"Molar mass of "H_(2)SO_(4))/("Molarity of solution")
= ((0.397g))/((98"g mol"^(-1))xx("0.5 mol"^(-1)))=0.0081L=0.0081xx1000=8.1" mL".

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