Question

Calculate the density `("in gm L"^(-1))` of a 3.60 M sulphuric acid solution that is 29 % `H_(2)SO_(4)` by mass `("molar mass = 98 g mol"^(-1))`

Answer 1

By definition, 3.6 M or `3.6 xx 98 = 352.8 g` of `H_(2)SO_(4)` are present in 1L of the solution
Now, 29g of `H_(2)SO_(4)` are present in the solution = 100 g
352.8 g of `H_(2)SO_(4)` are present in the solution `= ((100g)xx(352.8))/((29g))=1216g`
Density of solution `= ("Mass of solution")/("Volume of solution")=((1216g))/((1000mL))=1.22"g mL"^(-1)`