Question

Cadverine molecule has `58.77% C, 13.81% H` and `27% N` by mass Find Empirical formula of cadverine .

Answer 1

`{:("Element","Mole ratio","Divide by 1.9",,),(C,(58.77)/(12) = 4.9,(4.9)/(1.9) = 2.5,,),(H,(13.81)/(1) = 13.81,(13.81)/(1.9)=7,,),(N,(27)/(14)=1.9,(1.9)/(1.9)=1,,):}`
`:.` Empirical formula `=C_(2)H_(14) N_(2)` .