Question

The radical halogenation of 2-methyl propane gives two products `(CH_(3))_(2)CHCH_(2)X_(("minor"))` and `(CH_(3))_(3)CX_(("major"))`. Chlorination givs larger amount of the minor product than the bromination because
A. Bromide is more reactive than chlorine and is able to attack the less reactive `3^(@)C-H`
B. Brominie atoms are less reactive (more selective) than chlorine and preferentially atack the weaker `3^(@)C-H` bond.
C. The methyl groups are more hindered to attack by the larger bromine atom.
D. Bromination is reversible and more stable `3^(@)-` alkyl bromide is formed exlusively.

Answer 1

Correct Answer - B
Chlorine is more reactive, less selective bromine is less reactive, more selective