Correct Answer - D
`CH_3-overset(overset(O)||)C-ONa+NaOHunderset(Delta)overset(CaO)toCH_4+Na_2CO_3`
Mol. Mass of `CH_4=COONa=24+3+32+23=82`
Mol. Mass of `CH_4=12+4=16`
82 g of `CH_3COONO` produce = 16 g of `CH_4`
82 g of `CH_3COONO` produce = 16 g of `CH_4`
16 g of `CH_4-= 22.4 dm^(3) of `CH_4`
16 g of `CH_4-= 22.4 dm^(3) of `CH_4`