Data : d = 100λ, D = 50.0 cm
(a) The condition for maximum intensity in Young’s experiment is, d sin θ = nλ, n = 0, 1, 2....,
The angle between the central maximum and its adjacent maximum can be determined by setting n equal to 1,
∴ d sin θ = λ
(b) The distance between these maxima on the screen is D sin θ = D\(\left(\cfrac{\lambda}{d}\right)\)
= (50.0 cm)\(\left(\cfrac{\lambda}{100\lambda}\right)\)
= 0.50 cm