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The distance between two consecutive bright fringes in a biprism experiment using light of wavelength 6000 Å is 0.32 mm by how much will the distance change if light of wavelength 4800 Å is used?

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Data : λ1 = 6000 Å = 6 × 10-7 m, λ2 = 4800 Å = 4.8 × 10-7 m, W1 = 0.32 mm = 3.2 ×  10-4 m.

Distance between consecutive bright fringes,

∴ ∆W = W1 – W2

= 3.2 × 10-4 m – 2.56 × 10-4 m

= 0.64 × 10-4 m

= 6.4 × 10-5

= 0.064 mm

This is the required change in distance.

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