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One mole of a non-ideal gas undergoes a change of state `(2.0atm,3.0L,95K)rarr(4.0atm,5.0L,245K)`
With a change in internal energy `DeltaE=30L` atm. The change in enthalpy `(DeltaH)` in the process in `L`-atm is
A. `40.0`
B. `42.3`
C. `44.0`
D. Not defined, because pressure is not cosntant

1 Answer

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Best answer
Correct Answer - B
`DeltaH=DeltaE+Delta(PV)=DeltaE+(P_(2)V_(2)-P_(1)V_(1))`
or `DeltaH=30+(20-6)=30+14=44L`-atm.

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