Question

Red colored compound , hemoglobin present in blood contains `0.355% Fe (AM = 56u)` If four atoms of `Fe` are present per molucule of hemoglobin, its molecular mass would be
A. `63098 u`
B. `78654 u`
C. `54786 u`
D. `98036 u`

Answer 1

Correct Answer - A
As there are 4 atoms of `Fe` per molecule, we have
`% Fe = (4 xx AM of Fe)/("MM of hemoglobin") xx 100%`
(`AM` is atomic mass, `MM` is molar mass)
`0.335% = (4 (56u))/(MM) xx 100%`
`:. MM = (4(56u))/(0.335%) xx 100% = 63098 u`