Correct Answer - D
Total mass of `solution=1000 g water+120 g urea=1120 g`
Density of solution`=1.15 g//mL`
Thus, volume of solution=mass/density`=(1120g)/(1.15 g//mL)`
`=973.91 mL=0.974 L`
Moles of solute`=120/60=2 mol`
`"Molarity"=("moles of solute")/("volume (L) of solution")`
`=(2 "mol")/(0.974 L)=2.05 "mol" L^(-1)`