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An oxide of iodine `(I = 127` atoms) contains `42.3g` of idonie and `8g` of oxygen. Its formula could be
A. `I_(2)O_(5)`
B. `I_(2)O_(3)`
C. `I_(2)O_(7)`
D. `I_(2)O`

1 Answer

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Best answer
Correct Answer - B
Find the ratio of moles of `I` and O.
`n_(1) : n_(O) = (42.3)/(127) , (8)/(16) = 0.33: 0.500 = (0.333)/(0.333) , (0.500)/(0.333)`
`= 1: 1.50 = 2:3`

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