Use app×
Join Bloom Tuition
One on One Online Tuition
JEE MAIN 2025 Foundation Course
NEET 2025 Foundation Course
CLASS 12 FOUNDATION COURSE
CLASS 10 FOUNDATION COURSE
CLASS 9 FOUNDATION COURSE
CLASS 8 FOUNDATION COURSE
0 votes
142 views
in Chemistry by (73.6k points)
A `2.5g` sample containing `As_(2) O_(5) Na_(2) HAsO_(3)` and inert substance is dissolved in water and the `pH` is adjusted to neutral with excess of `NaHCO_(3)`. The solution is titrated with `0.15M I_(2)` solution, requiring `11.3 mL` to just reach the end point, then the solution is acidified with `HCl, KI` is added and the liberated iodine requires `41.2 mL` fo `0.015M Na_(2)S_(2)O_(3)` under basic conditions where it converts to `SO_(4)^(2-)`. Calculate per cent compositon of mixture.

Please log in or register to answer this question.

1 Answer

0 votes
by (70.6k points)
Correct Answer - `Na_(2) HAsO_(3) = 11.53%, As_(2)O_(5) = 3.57%`
inert material `= 84.9%`

Welcome to Sarthaks eConnect: A unique platform where students can interact with teachers/experts/students to get solutions to their queries. Students (upto class 10+2) preparing for All Government Exams, CBSE Board Exam, ICSE Board Exam, State Board Exam, JEE (Mains+Advance) and NEET can ask questions from any subject and get quick answers by subject teachers/ experts/mentors/students.

Categories

...