How many millilitres of 0.5 M `KMnO_(4)` are needed to react with 3.04 gms of iron (II) sulphate , `FeSO_(4)`? The reaction is as follows?
`10FeSO_(4)(aq) + 2KMnO_(4)(aq) + 8H_(2)SO_(4)(aq) rarr 5Fe_(2)(SO_(4))_(3)(aq) + 2MnSO_(4)(aq)+K_(2)SO_(4)(aq) + 8H_(2)O(l)`