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The value of tan2(sec-12)+cot2(cosec-13) is:

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Best answer

 tan2(sec-12) = sec2(sec-12) - 1 

cot2(cosec-13) = cosec2(cosec-13) - 1   

Therefore, 

tan2(sec-12) + cot2(cosec-13) 

= sec2(sec-12) - 1 + cosec2(cosec-13) - 1 

= [sec(sec-12)]2 + [cosec(cosec-13)]2 - 2 

= (2)2 + (3)2 - 2 

= 4 + 9 - 2 

= 11

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