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The oxidation number of nitrogen atom in `NH_(4)NO_(3)` are:

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The oxidation number of nitrogen atom in `NH_(4)NO_(3)` are:
A. `+3,+3`
B. `+3,-3`
C. `-3,+5`
D. `-5,+3`
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Correct Answer - C
`NH_(4)NO_(3) Leftrightarrow NH_(4)^(+)+NO_(3)^(-)`
`NH_(4)^(+)x+4=+1`
x=-3
`NH_(3)^(-)x+6=-1`
x=+5
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