Question

`Fe^(3+)` is reduced to `Fe^(2+)` of NaOH
A. `H_(2)O_(2)` is presence of NaOH
B. `Na_(2)O_(2)` in water
C. `H_(2)O_(2)` in presence of `H_(2)SO_(4)`
D. `Na_(2)O_(2)` in presence of `H_(2)SO_(4)`

Answer 1

Correct Answer - A::B
In basic medium `H_(2)O_(2)` acts as reducing agent.
`Na_(2)O_(2)+2H_(2)O to 2NaOH+H_(2)O_(2)`
`2Fe^(3+)+H_(2)O_(2)+2OH^(-) to 2Fe^(2+)+2H_(2)O+O_(2)`