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How many unit cells are present in 39 g of potassium that crystallises in body-centred cubic structure ?

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How many unit cells are present in 39 g of potassium that crystallises in body-centred cubic structure ?
A. `N_(A)`
B. `(N_(A))/(4)`
C. `0.5 N_(A)`
D. `0.75 N_(A)`
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Correct Answer - C
Number of atoms `=("Mass")/("Atomic mass")xxN_(A)=(39)/(39)xxN_(A)=N_(A)`
In bcc unit cell, Z=2
`therefore` Number of unit cells `=(N_(A))/(2)=0.5 N_(A)`
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