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A face-centred cubic element (atomic mass `60`) has a cell edge of `400` pm. What is its density?

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Correct Answer - `6.23 g cm^(-3)`
Apply density `=(ZxxM)/(N_(0)xxV),Z=4 and V=(4xx10^(-8))^(3) cm^(3)`
`(1 "pm"=10^(-12)m=10^(-10) cm)`

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