Question

0.05 mole of NaOH is added to 5 liters of water What will be the pH of the solution ?
A. 12
B. 7
C. 2
D. 10

Answer 1

Correct Answer - A
Conc. of `NaOH=(0.05)/(5)=0.01or10^(-2)M`
`[OH^(-)]=10^(-2)M`
`[H^(+)]=(K_(w))/([OH^(-)])=(10^(-14))/(10^(-2))=10^(-12)`
`pH=-log[H^(+)]=-log10^(-12)=12`

Comments

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