Question

Calculate the uncertainty in the position of a particle when the uncertaintly in momentum it:
(a). `1xx10^(-3)g" cm "sec^(-1)`
(b) zero.

Answer 1

(a). Given,
`DeltaP=1xx10^(-3)g" cm "sec^(-1)`
`h=6.62xx10^(-27)erg-sec`
`pi=3.142`
According to uncertainty principle,
`Deltax*Deltap ge (h)/(4pi)`
So, `Delta ge (h)/(4pi)*(1)/(Deltap)ge (6.62xx10^(-27))/(4xx3.142)xx(1)/(10^(-3))`
`=0.527xx10^(-24)cm`
(b). When the value of `Deltap=0`, the value of `Deltax` will be infinity.