Question

Three blocks of equal masses (each `3kg`) are suspended by weightless strings as shown. If applied force is `100N`,then `T_(1)` is equal to `(g=10m//s^(2))`

A. `130 N`
B. `190 N`
C. `100 N`
D. `160 N`

Answer 1

Correct Answer - A
`T_(1)=F+mg`