Question

A steel rod of cross sectional area `4cm^2 and `length 2m shrinks by 0.1 cm as the temperature decreases in night. If the rod is clamped at both ends during the day horus, find the tension developed in it during night hours. Young modulus of steel `=1.9xx10611` nm^-2`

Answer 1

Correct Answer - A::C::D
`A=4cm^2=4x10^-4, L=2m`
`=/_L=0.1cm=10^-3, Y=1.9xx10^11`
`Y=F/AxxL/(/_L)`
`rarr F=(YA/_L)/L`
`(1.9xx10^11xx4xx10^-4xx10^-3)/2`
`=3.8xx10^4N`
The tension developed is `3.8xx10^4N`