Use app×
Join Bloom Tuition
One on One Online Tuition
JEE MAIN 2025 Foundation Course
NEET 2025 Foundation Course
CLASS 12 FOUNDATION COURSE
CLASS 10 FOUNDATION COURSE
CLASS 9 FOUNDATION COURSE
CLASS 8 FOUNDATION COURSE
0 votes
77 views
in Physics by (67.6k points)
closed by
image
A uniform rod of legth `L` is free to rotate in a vertica plane about a fixed horizontal axis through `B`. The rod begins rotating from rest. The angular velocity `omega` at angle `theta` is given as
A. `sqrt(((6g)/(L)))sin((theta)/(2))`
B. `sqrt(((6g)/(L)))cos((theta)/(2))`
C. `sqrt(((6g)/(L)))sintheta`
D. `sqrt(((6g)/(L)))costheta`

1 Answer

0 votes
by (75.1k points)
selected by
 
Best answer
Decrease in gravitational kinetic energy
`=` increase in rotational kinetic energy
`therefore((l)/(2)-(l)/(2)costheta)=(1)/(2)Iomega^(2)`
`=(1)/(2)((ml^(2))/(3))omega^(2)`
`omega=sqrt((6g)/(L))sin((theta)/(2))`

Welcome to Sarthaks eConnect: A unique platform where students can interact with teachers/experts/students to get solutions to their queries. Students (upto class 10+2) preparing for All Government Exams, CBSE Board Exam, ICSE Board Exam, State Board Exam, JEE (Mains+Advance) and NEET can ask questions from any subject and get quick answers by subject teachers/ experts/mentors/students.

Categories

...