Question

The gravitational field due to a mass distribution is `E=K//x^(3)` in the x - direction. ( K is a constant). Taking the gravitational potential to be zero at infinity, its value at a distance x is

Answer 1

The potential at a distance x is
`V(x)=-int_oo^x E dx=-int_oo^x K/x^3 dx`
`=[K/(2x^2)]_oo^x=K/(2x^2)`