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A sound wave in air has a frequency of `300 H_(Z)` and a displacement ampulitude of `6.0 xx10^(-3) mm`. For this sound waves calculate the (a) Pressure ampulitude (b) intensity (c ) Sound intensity level (in dB)
Speed of sound `= 344 m//s` and density of air `= 1.2 kg//m^(3)`.

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Correct Answer - A::B::C::D
`Delta p_(max) = Bak`
`= (rho nu)^(2) (A)((omega)/(nu))`
`= (2 pi f A rho nu)`
`= (2 pi) (300)(6.0 xx 10^(-3)(1.2)(344)`
`= 4.67 Pa`
(b) `I = (nu(Deltap)^(2)max)/(2B)`
`= ((Deltap)^(2)max)/(2 rho nu)` (as `B = rho nu^(2))`
`= (4.67)^(2)/((2)(1.2)(344)`
`= 0.0264 w//m^(2)`
`= 2.64 xx 10^(-2) W//m^(2)`
(c ) `L = log_(10) ((I)/(I_(0)))`
`= 10 log_(10) ((2.64 xx 10^(-2))/(10^(-12)))`
`= 104 dB`

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