Question

Two masses `m_(1)` and `m_(2)(m_(1)ltm_(2))` are released from rest finite distance. They start under their mutual gravitational attraction-
A. acceleration of `m_(1)` is more than that of `m_(2)`
B. acceleration of `m_(2)` is more than that of `m_(1)`
C. centre of mass of system will remain at rest in all the references frame.
D. total energy of system remains constant

Answer 1

Correct Answer - a,d

(A) `a_(1)=(f_(g))/(m_(1))` and `a_(2)=(f_(g))/(m_(2))` since `m_(1)ltm_(2)` so `a_(1)gt a_(2)`
(D) total energy of system remains constant. So choice `(A)` and `(D)` are correct.