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Silver crystallises in fcc lattice. If edge length of the cell is 4.07 × 10−8 cm and density is 10.5 g cm−3, calculate the atomic mass of silver.

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It is given that the edge length, a = 4.077 × 10−8 cm Density,

 d = 10.5 g cm−3 

As the lattice is fcc type, the number of atoms per unit cell, z = 4

 We also know that

 NA = 6.022 × 1023 mol−1 Using the relation:

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