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Two black balls can be selected out of 5 black balls in 5C2 ways.Similarly, 3 red balls can be selected out of 6 red balls in 6C3 ways.Therefore the number of ways in which 2 black balls and 3 red balls can be drawn is 5C2 × 6C3
Now 5C2 × 6C13 

= 10 × 20 = 200
Thus, out of 5 black and 6 red balls, 2 black and 3 red balls can be selected in 200 ways.

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