**Solution:**

Two black balls can be selected out of 5 black balls in ^{5}C_{2} ways.Similarly, 3 red balls can be selected out of 6 red balls in ^{6}C_{3} ways.Therefore the number of ways in which 2 black balls and 3 red balls can be drawn is ^{5}C_{2} × ^{6}C_{3} .

Now ^{5}C_{2} × ^{6}C_{13}

=

= 10 × 20 = 200

Thus, out of 5 black and 6 red balls, 2 black and 3 red balls can be selected in 200 ways.