Use app×
Join Bloom Tuition
One on One Online Tuition
JEE MAIN 2025 Foundation Course
NEET 2025 Foundation Course
CLASS 12 FOUNDATION COURSE
CLASS 10 FOUNDATION COURSE
CLASS 9 FOUNDATION COURSE
CLASS 8 FOUNDATION COURSE
0 votes
63 views
in Physics by (85.7k points)
closed
Hot water cools from `60^@C` to `50^@C` in the first 10 min and to `42^@C` in the next 10 min. The temperature of the surrounding is
A. `5^@C`
B. `10^@C`
C. `15^@C`
D. `20^@C`

1 Answer

0 votes
by (90.5k points)
 
Best answer
Correct Answer - B
`(theta_1-theta_2)/(t)prop[(theta_1+theta_2)/(2)-theta]`
for the first condition
`(60-50)/(10)prop[(60-50)/(2)-theta]implies1=K[55-theta]` .(i)
For the second condition
`(50-42)/(10)prop[(50+42)/(2)-theta]implies0.8=K(46-theta)` .(ii)
From Eqs. (i) and (ii), we get `theta=10^@C`

Welcome to Sarthaks eConnect: A unique platform where students can interact with teachers/experts/students to get solutions to their queries. Students (upto class 10+2) preparing for All Government Exams, CBSE Board Exam, ICSE Board Exam, State Board Exam, JEE (Mains+Advance) and NEET can ask questions from any subject and get quick answers by subject teachers/ experts/mentors/students.

Categories

...