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Three copper blocks of masses `M_(1), M_(2) and M_(3) kg` respectively are brought into thermal contact till they reach equlibrium. Before contact, they were at `T_(1), T_(2), T)(3),(T_(1)gtT_(2)gtT_(3))`. Assuming there is no heat loss to the surroundings, the equilibrium temperature `T` is `(s is specific heat of copper)`
A. `T = (T_(1)+T_(2)+T_(3))/(3)`
B. `T=(M_(1)T_(1)+M_(2)T_(2)+M_(3)T_(3))/(M_(1)+M_(2)+M_(3))`
C. `T = (M_(1)T_(1)+M_(2)T_(2)+M_(3)T_(3))/(3(M_(1)+M_(2)+M_(3)))`
D. `T = (M_(1)T_(1)s + M_(2)T_(2)s + M_(3)T_(3)s)/(M_(1)+M_(2)+M_(3))`

1 Answer

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by (90.2k points)
 
Best answer
Correct Answer - B
`T = (M_(1)S_(1)T_(1)+M_(1)S_(2)T_(2) + M_(3)S_(3)T_(3))/(M_(1)S_(1)+M_(2)S_(2)+M_(3)S_(3))`.

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