Question

Two masses `m_(1)` and `m_(2)(m_(1)ltm_(2))` are released from rest finite distance. They start under their mutual gravitational attraction-
A. acceleration of `m_(1)` is more than that of `m_(2)`
B. acceleration of `m_(2)` is more than that of `m_(1)`
C. centre of mass of system will remain at rest in all the reference frame
D. total enery of system remains constant

Answer 1

Correct Answer - A::D

(A) `a_(1) = (f_(g))/(m_(1))` and `a_(2) = (f_(g))/(m_(2))` snce `m_(1) lt m_(2)` so `a_(1) gt a_(2)`
(D) Total energy of system remains constant.