Question

The work of 146 kJ is performed in order to compress one kilo mole of a gas adiabatically and in this process the temperature of the gas increases by `7^@C`. The gas is `(R=8.3ml^-1Jmol^-1K^-1)`
A. Triatomic
B. A mixture of monoatomic and idatomic
C. Monoatomic
D. Diatomic

Answer 1

Correct Answer - D
`n=10^3,DeltaW=-146xx10^3J,DeltaT=T_2-T_1=7^@C`
`DeltaW=(nR(T_1-T_2))/(gamma-1)=-(nR(T_2-T_1))/(gamma-1)`
`-146xx10^3=-(10^3xx8.3xx7)/(gamma-1)`
`gamma-1=0.4`
`gamma=1.4`, diatomic gas