LIVE Course for free

Rated by 1 million+ students
Get app now
0 votes
494 views
in Physics by (85.2k points)
closed
An object moves from position (6,8) to (12,10) in the x-y plane. Magnitude and direction of displacement is
A. `sqrt(40)` and `18.43^(@)`
B. `sqrt(40)` and `61.56^(@)`
C. 10 and `53^(@)`
D. `sqrt(244)` and `53^(@)`

1 Answer

0 votes
by (90.0k points)
 
Best answer
Correct Answer - A
Positions of the particle are
`r_(1) = 6 hati +8hatj` and `r_(2) = 12 hati +10 hatj`
`:. Deltar = r_(2) - r_(1) = 6 hati + 2hatj rArr |Deltar| = sqrt(40)`
`theta = tan^(-1) ((Delta y)/(Deltax)) = tan^(-1) ((1)/(3)) = 18.43^(@)`

Welcome to Sarthaks eConnect: A unique platform where students can interact with teachers/experts/students to get solutions to their queries. Students (upto class 10+2) preparing for All Government Exams, CBSE Board Exam, ICSE Board Exam, State Board Exam, JEE (Mains+Advance) and NEET can ask questions from any subject and get quick answers by subject teachers/ experts/mentors/students.

Categories

...