Question

A constant retarding force of 50 N is applied to a body of mass 20 kg moving initially with a speed of `15ms^(-1)` How long does the body take to stop ?
A. 6s
B. 8s
C. 9s
D. 10s

Answer 1

Correct Answer - A
(a) Give, F=50N, m=20 kg, v=`15 ms^(-1)`
Impule `F=(mv)/( Deltat)`
Time `Deltat=(mv)/(F)`
`Deltat=(20xx15)/(50)=6s`