Question

A fixed mortar fires a bomb at an angle of `53^@` above the horizontal with a muzzle velocity of `80 ms^-1`. A tank is advancing directly towards the mortar on level ground at a constant speed of `5m//s`. The initial separation (at the instant mortar is fired) between the mortar and tank, so that the tank would be hit is `[Take g = 10 ms^-2]`
A. 662.4m
B. 526.3m
C. 486.6m
D. None of these

Answer 1

Correct Answer - D
`T = (2usintheta)/g = ((2)(8)sin 53^@)/10 = 1.28s`
`R = (u^2sin2theta)/g = ((80)^2 sin (106^@))/10 = 615.2 m`
Distance travelled by tank,
`d = (5)T = (5)(1.28) = 6.4m`
`:.` Total distance `= (615.2 + 6.4)m`
`=621.6m`.