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Find the total elongation of the bar, if the bar is subjected to axical froces as shown in figure . The cross-section area of bar is `10 cm^(2)` .
`[Take E = 8 xx 10 ^(2) "dyne"//cm^(2)]`
image
A. 0.01 cm
B. 0.5 cm
C. 0.0675 cm
D. 0.775 cm

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Correct Answer - C
Let `deltal`= total enlogation of the bar, A = area,
`E= 8 xx 10^(2)`. Let make the free body diagram .
image
Using equation `deltal= (1)/(AE)(F_(1)l_(1) + F_(2)l_(2) + F_(3)l_(3))`
`deltal =(1)/(10 xx 8 xx 10 ^(2))(5 xx 60 + 2 xx 60 + 1 xx120)`
`deltal=0.0675 cm`

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