Fewpal
+3 votes
64 views
in Mathematics by (127k points)

How many 6-digit numbers can be formed from the digits 0, 1, 3, 5, 7 and 9 which are divisible by 10 and no digit is repeated ?

1 Answer

+3 votes
by (9.9k points)
selected by
 
Best answer

Let the six digit number be abcdef
'a' can take all values except 0 since it will not be a 6 digit number then. So this means it can take any of 5 values.
'b' can take one the remaining 5 digits.
'c' can take any of the remaining 4
Similarly 'd' can take 3, 'e' can take 2 and 5'f' can take 1 value

So this means the total numbers that can be formed are :
5*5*4*3*2*1 = 600

For the numbers divisible by 10:
The last digit should be always 0
In this case the total possibilities are: 5*4*3*2*1*1 = 120

Welcome to Sarthaks eConnect: A unique platform where students can interact with teachers/experts/students to get solutions to their queries. Students (upto class 10+2) preparing for All Government Exams, CBSE Board Exam, ICSE Board Exam, State Board Exam, JEE (Mains+Advance) and NEET can ask questions from any subject and get quick answers by subject teachers/ experts/mentors/students.

Categories

...