Correct Answer - B::C
Thermal resistance of plastic coating`(R_t = l/(KA))`
`R_t = t/(K(pid)l)` (d = diameter)
`(0.6xx10^(3))/((0.16xx10^(-2)xx4.18xx10^(2))(pi)(0.64xx10^(-3))(2))`
`=0.0223^@C-s//J`
Now, `i^2R_e = (TD)/R_t`
`:. TD = i^2R_eR_t`
`=(5)^2(4)(0.0223)`
`=2.23^@C`